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CGP EDU Academic Team
Published on: August 13, 2026
If in Δ ABC, cos(A – C) cos B + cos 2B = 0 then a 2 , b 2 , c 2 are in-
Text Solution
Verified by ExpertsThe correct answer is:
A
–cos(A – C) cos(A + C) + 1 – 2sin 2 B = 0
–[cos 2 A – sin 2 C] + 1 – 2sin 2 B = 0
sin 2 A + sin 2 C = 2 sin 2 B
∴ a 2 + c 2 = 2b 2 a
2 , b 2 , c 2 are in A.P.
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